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Thailand reports 374 new COVID-19 cases


rooster59

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8 hours ago, Stev Lam said:

Wonder why Thailand deliberately attempted NOT to report cases from yesterday afternoon in addition to today's cases "Late Saturday afternoon, the Samut Sakhon provincial health office reported 335 new COVID-19 cases"

Total cases today (17 January), shouldn't it be 709???

Why Thailand always play down in reporting numbers? Isn't Samut Sakhon part of Thailand??? Does not matter, if ii is from migrant workers, the total infection cases should be reported accurately, then the breakdown by province can be detailed to make up the grand total.

I remember that Singapore always separated migrant workers and local infection, imported. Why? 

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12 hours ago, UB40 said:

All because of that "super PCR test"

Developed by a German "Doctor" at beginn of Jan 2020 ---》first data's were available end of January 2020. 

 

The PCR test isn't suitable to show an active virus. After 40 exp40 multiplying it only can show antibodies, without stating anything.

 

But its useless writing more. People love to be lied to

 

 

You need to lay off the Red Red Wine...

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14 hours ago, G950 said:

To be fair 320 out of the 374 were found amongst migrant workers already locked down in Samut Sakhon. 

 

The remaining 50 or so from local infections in relatively low. 

 

I am not trying to downplay the situation but the numbers outside of Samut Sakhon seem to be stable meaning and relatively low.


That is what we were thinking in Europe too ... 

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16 hours ago, morrobay said:

From the data for 34 days, 28 new infections on 15 Dec and 7808 additional on Jan 17. Given an infection/transmission period of four days there would be 8.5 periods. So 28(R0)^8.5 = 7808. Then 8.5(logR0)=log(278.8) Therefore logR0=2.445/8.5 = .28764 So the R0 equals 1.94 

What's that in English?

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11 hours ago, hotchilli said:

What's that in English?

https://en.m.wikipedia.org/wiki/Basic_reproduction_number. Scroll to the blue red diagram for ebola. The R0 is 2 as can be seen where each infected person infects two more in each infect period. After two infection periods there are four new infections. Now start with 10 infected people with R0=2 then the new infections are 40 after two infection periods: 10 (2)^2 =40. Suppose the R0 is not given or obvious by inspection. Then you have to solve: 10(R0)^2=40. And is with a little algebra: (R0)^2 = 4. Then 2(logR0)=log4. The log of 4 is .602 So the logR0 is .602/2 = .301 So if the log of the R0 is .301 then the number,R0, is 10^.301 = 2

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12 hours ago, morrobay said:

https://en.m.wikipedia.org/wiki/Basic_reproduction_number. Scroll to the blue red diagram for ebola. The R0 is 2 as can be seen where each infected person infects two more in each infect period. After two infection periods there are four new infections. Now start with 10 infected people with R0=2 then the new infections are 40 after two infection periods: 10 (2)^2 =40. Suppose the R0 is not given or obvious by inspection. Then you have to solve: 10(R0)^2=40. And is with a little algebra: (R0)^2 = 4. Then 2(logR0)=log4. The log of 4 is .602 So the logR0 is .602/2 = .301 So if the log of the R0 is .301 then the number,R0, is 10^.301 = 2

????

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