pomchop Posted July 17, 2013 Share Posted July 17, 2013 If a lot is 50 feet x 94 x 140 x 100 how many square meters would that be? Anyone know how to calculate? Link to comment Share on other sites More sharing options...
mikekim1219 Posted July 17, 2013 Share Posted July 17, 2013 8,159.298 sqf or 758 sqm Link to comment Share on other sites More sharing options...
toybits Posted July 18, 2013 Share Posted July 18, 2013 What you need to do is draw the lot on paper - I assume you already have done that, the break it up into either Triangles and rectangles. Getting the area of a rectangle is relatively easy. What about the triangle? If it is a right Triangle (meaning, one of the angles is 90 degrees, simply imagine a duplicate mirror image of that triangle to double the area of the right triangle. What you end up with is another rectangle. Calculate for area - the divide by two to get area of right triangle. If the triangle is not a right triangle, it is a bit more complicated... But what you should try to do is redivide that triangle to get two right triangle. Am I triangling you out??? 1 Link to comment Share on other sites More sharing options...
mikekim1219 Posted July 18, 2013 Share Posted July 18, 2013 Simple method is using Brahmaguta's formula. Area is equal to square root of (s-a)(s-(s-c)(s-d) a,b,c,d are the length of the four size and where: s = (a+b+c+d)/2 Hence you get square feet of 8,159 sqt. convert it to meter, it is 758 sqm minus the decimals. Link to comment Share on other sites More sharing options...
johnlandy Posted July 18, 2013 Share Posted July 18, 2013 (edited) 8,159.298 sqf or 758 sqm 8,159.298 sqf or 758 sqm The question was does "anyone know how to calculate" (the land size) not what the land size is The response "simple method is using Brahmaguta's formula" I don't think he was expecting an answer from Einstein The OP has made the question unnecessarily confusing by putting in extraneous dimensions when he could have (should have) just said, e.g. 50' x 140' which would be converted into metric and that would give the area. But "stupid is, as stupid does" Edited July 18, 2013 by johnlandy Link to comment Share on other sites More sharing options...
pomchop Posted July 18, 2013 Author Share Posted July 18, 2013 8,159.298 sqf or 758 sqm thank you Link to comment Share on other sites More sharing options...
oneday Posted July 18, 2013 Share Posted July 18, 2013 How can you know this formula mikekin1219 and NOT know this only works for a "cyclic quadrilateral"? In other words it must be able to be inscribed inside a circle. It's unlikely this one can be inscribed within a circle. OP you need to follow what "toybits" said. Link to comment Share on other sites More sharing options...
Popular Post pomchop Posted July 18, 2013 Author Popular Post Share Posted July 18, 2013 8,159.298 sqf or 758 sqm 8,159.298 sqf or 758 sqm The question was does "anyone know how to calculate" (the land size) not what the land size is The response "simple method is using Brahmaguta's formula" I don't think he was expecting an answer from Einstein alt=clap2.gif width=31 height=25> The OP has made the question unnecessarily confusing by putting in extraneous dimensions when he could have (should have) just said, e.g. 50' x 140' which would be converted into metric and that would give the area. But "stupid is, as stupid does" alt=coffee1.gif width=32 height=24> actually the main questions was: If a lot is 50 feet x 94 x 140 x 100 how many square meters would that be? And though I may be "stupid" I don't think your simple 50 x140 converted to metric is correct. The lot is not a perfect rectangle. So perhaps you are correct that" stupid is as stupid does." 4 Link to comment Share on other sites More sharing options...
pomchop Posted July 18, 2013 Author Share Posted July 18, 2013 8,159.298 sqf or 758 sqm 8,159.298 sqf or 758 sqm The question was does "anyone know how to calculate" (the land size) not what the land size is The response "simple method is using Brahmaguta's formula" I don't think he was expecting an answer from Einstein alt=clap2.gif width=31 height=25> The OP has made the question unnecessarily confusing by putting in extraneous dimensions when he could have (should have) just said, e.g. 50' x 140' which would be converted into metric and that would give the area. But "stupid is, as stupid does" alt=coffee1.gif width=32 height=24> actually the main questions was: If a lot is 50 feet x 94 x 140 x 100 how many square meters would that be? And though I may be "stupid" I don't think your simple 50 x140 converted to metric is correct. The lot is not a perfect rectangle. So perhaps you are correct that" stupid is as stupid does." Link to comment Share on other sites More sharing options...
pomchop Posted July 18, 2013 Author Share Posted July 18, 2013 sorry for double post... i don't begin to claim to understand all the math equations you guys are talking about...i do appreciate the positive answers and calculations...so is the correct answer approx. 758 square meters? Link to comment Share on other sites More sharing options...
sunsamourai Posted July 18, 2013 Share Posted July 18, 2013 draw a polyline in autocad or equivalent, click properties, you got your area. Change units to metrics if still in imperial. done. Link to comment Share on other sites More sharing options...
ShopBoy Posted July 18, 2013 Share Posted July 18, 2013 draw a polyline in autocad or equivalent, click properties, you got your area. Change units to metrics if still in imperial. done. you expect layman to have autocad or equivalent installed to just calculate the area size ? 1 Link to comment Share on other sites More sharing options...
Fiddlesticks Posted July 18, 2013 Share Posted July 18, 2013 sorry for double post... i don't begin to claim to understand all the math equations you guys are talking about...i do appreciate the positive answers and calculations...so is the correct answer approx. 758 square meters? Without knowing two of the angles from the lot, it will difficult to calculate the exact area but 758 square meters is a close approximation (probably as close as you will get ! Link to comment Share on other sites More sharing options...
Lalo27 Posted July 18, 2013 Share Posted July 18, 2013 Well, at the end we still don't know how to calculate the area of an totally irregular parallelepiped. ..! You do have to divide into triangles but if a right triangle is super easy to calculate, others are not that easy and especially when you are talking about plots of land with trees, bushes and water around. I am interested to find an easy way as well... Link to comment Share on other sites More sharing options...
Shiver Posted July 18, 2013 Share Posted July 18, 2013 (edited) If you google "calculate area of irregular polygon", it quickly becomes clear that there is no simple way to do that without getting into serious maths. If you don't have access to an app like Acad, then what I would do is get a simple drawing app (like MSPaint that is standard with windows, or even a pencil and paper with grid lines on it) and decide on units for each square, Say a big square = 10ft, and a small square =1ft, you can get an approximate answer. If you know how to do vertices, then you can do it online as shown here http://www.wikihow.com/Calculate-the-Area-of-a-Polygon Edited July 18, 2013 by Shiver Link to comment Share on other sites More sharing options...
mikekim1219 Posted July 18, 2013 Share Posted July 18, 2013 .so is the correct answer approx. 758 square meters? Yes, that's correct Link to comment Share on other sites More sharing options...
mikekim1219 Posted July 18, 2013 Share Posted July 18, 2013 If you google "calculate area of irregular polygon", it quickly becomes clear that there is no simple way to do that without getting into serious maths. If you don't have access to an app like Acad, then what I would do is get a simple drawing app (like MSPaint that is standard with windows, or even a pencil and paper with grid lines on it) and decide on units for each square, Say a big square = 10ft, and a small square =1ft, you can get an approximate answer. If you know how to do vertices, then you can do it online as shown here http://www.wikihow.com/Calculate-the-Area-of-a-Polygon All you need is calculator with square root feature and use Brahmaguta's formula as stated in my reply to Pomchop. Link to comment Share on other sites More sharing options...
lineofentry Posted July 18, 2013 Share Posted July 18, 2013 Draw it on graph paper, count the squares. Yawn. 1 Link to comment Share on other sites More sharing options...
pomchop Posted July 18, 2013 Author Share Posted July 18, 2013 Thanks guys...i'll let you math gurus figure the finer details but for my purposes I will just go with 758 square meters. Link to comment Share on other sites More sharing options...
HerbalEd Posted July 18, 2013 Share Posted July 18, 2013 (edited) Since the area is not a square or rectangle, you must know the degree of at least one angle to calculate the area's size. At least, that's how I'd do it. Maybe there's another way? Edited July 18, 2013 by HerbalEd Link to comment Share on other sites More sharing options...
petertucker48 Posted July 19, 2013 Share Posted July 19, 2013 How has any rectangle got 4 dimensions ? 1 Link to comment Share on other sites More sharing options...
petertucker48 Posted July 19, 2013 Share Posted July 19, 2013 Sorry 4 Different dimensions. Link to comment Share on other sites More sharing options...
Moouan Posted July 19, 2013 Share Posted July 19, 2013 (edited) Add all the dimensions together and take that new dimension as the circumference of a circle then apply formula below: C = 2pir ( 2 x pi x r) So knowing the circumference, you can find the radius and this is all you need to find the area. Area = pir^2 ( pi x radius^2) Edited July 19, 2013 by Moouan Link to comment Share on other sites More sharing options...
oxymoron Posted July 19, 2013 Share Posted July 19, 2013 Add all the dimensions together and take that new dimension as the circumference of a circle then apply formula below: C = 2pir ( 2 x pi x r) So knowing the circumference, you can find the radius and this is all you need to find the area. Area = pir^2 ( pi x radius^2) Rubbish, try testing your hypothesis Link to comment Share on other sites More sharing options...
DGIE Posted July 19, 2013 Share Posted July 19, 2013 ....?????!!!!! Link to comment Share on other sites More sharing options...
Sophon Posted July 19, 2013 Share Posted July 19, 2013 (edited) sorry for double post... i don't begin to claim to understand all the math equations you guys are talking about...i do appreciate the positive answers and calculations...so is the correct answer approx. 758 square meters? No, the correct answer is that with the information you have given it's impossible to calculate the area of your land. With an irregular polygon it's not enough to know the length of the (in this case four) sides, you also need to know the angels at some of the corners. There are calculators on the net e.g. this one, that will calculate the area for you given enough information. Here are a couple of examples, just to show you how different the results can be depending on the angels. First example, a somewhat "regular" shape where the angels are close to 90 degrees: As you can see the area of this land is 8,159 sq.feet or 758 sq.m. Second example, where the sum of the opposing angels are changed from 180 degrees to a somewhat extreme 30 degrees: Now your land (without changing the length of any of the sides) is only 2,276 sq.feet or 211 sq.m. Sophon Edited July 19, 2013 by Sophon 1 Link to comment Share on other sites More sharing options...
wayned Posted July 19, 2013 Share Posted July 19, 2013 (edited) Here's the area if one of the angles is 90 degrees; Use the law of cosines to find the diagonal length AC: SQRT( 502 + 942 - 2(50)(94)cos(90) ) = 106.47. With the diagonal, the lot is divided into two triangles and I know all the lengths of the sides of these triangles, so I can use Heron's formula to find the area of each triangle: SABC = (50 + 94 + 106.47) / 2 = 125.24 AABC = SQRT( (125.24)(125.24 - 50)(125.24 - 94)(125.24 - 106.47) ) = 2350.0. SACD = (106.47 + 140 + 100) / 2 = 173.24 AACD = SQRT( (173.24)(173.24 - 106.47)(173.24 - 140)(173.24 - 100) ) = 5305.8. That makes a total for the two triangles (which is the area of your property) of: 2350.0 + 5305.8= 7655.8 square feet= 850.65 square yards= 711.25 square meters= 0.17575 acres= 0.071125 hectares Go to this website, enter the four sides and one of the angles and it will calculate it for you: http://mathcentral.uregina.ca/QQ/database/QQ.09.06/s/foursidedlot.php Edited July 19, 2013 by wayned Link to comment Share on other sites More sharing options...
Sophon Posted July 19, 2013 Share Posted July 19, 2013 Here's the area if one of the angles is 90 degrees; Use the law of cosines to find the diagonal length AC: SQRT( 502 + 942 - 2(50)(94)cos(90) ) = 106.47. With the diagonal, the lot is divided into two triangles and I know all the lengths of the sides of these triangles, so I can use Heron's formula to find the area of each triangle: SABC = (50 + 94 + 106.47) / 2 = 125.24 AABC = SQRT( (125.24)(125.24 - 50)(125.24 - 94)(125.24 - 106.47) ) = 2350.0. SACD = (106.47 + 140 + 100) / 2 = 173.24 AACD = SQRT( (173.24)(173.24 - 106.47)(173.24 - 140)(173.24 - 100) ) = 5305.8. That makes a total for the two triangles (which is the area of your property) of: 2350.0 + 5305.8 = 7655.8 square feet = 850.65 square yards = 711.25 square meters = 0.17575 acres = 0.071125 hectares Go to this website, enter the four sides and one of the angles and it will calculate it for you: http://mathcentral.uregina.ca/QQ/database/QQ.09.06/s/foursidedlot.php Note that you cannot really calculate the area with just one angle, that is why the website you link to is making the assumption that the shape of the land is convex to get around needing the second angle. Also, you write "Here's the area if one of the angles is 90 degrees", but the area will actually differ depending on which of the angles it is that is 90 degrees. Sophon Link to comment Share on other sites More sharing options...
pomchop Posted July 19, 2013 Author Share Posted July 19, 2013 Ok for all you math gurus here is a pic of the actual lot...not sure if you can calculate the angles you guys are talking about from this or not....but this is all the info I have....the measurements are all shown in feet as the lot is in the USA. I'm ok with the previous 758 sm but if anyone wants to keep calculating go for it. Link to comment Share on other sites More sharing options...
mikekim1219 Posted July 19, 2013 Share Posted July 19, 2013 Ok for all you math gurus here is a pic of the actual lot...not sure if you can calculate the angles you guys are talking about from this or not....but this is all the info I have....the measurements are all shown in feet as the lot is in the USA. I'm ok with the previous 758 sm but if anyone wants to keep calculating go for it. Pomchop, 758 sqm is area if it's cyclic quadrilateral shape. If it's not, you need to know at least one of the diagonal length or angel of any one of the corners. Looking at your picture it may not be cyclic quadrilateral meaning all four vertices must lie in a circle. Best way to be sure is measure the distance of any two points. Link to comment Share on other sites More sharing options...
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